6(v+3)=-4(5v-1)+8v

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Solution for 6(v+3)=-4(5v-1)+8v equation: 



6(v+3)=-4(5v-1)+8v

We move all terms to the left:

6(v+3)-(-4(5v-1)+8v)=0

We multiply parentheses

6v-(-4(5v-1)+8v)+18=0



We calculate terms in parentheses: -(-4(5v-1)+8v), so:

-4(5v-1)+8v

We add all the numbers together, and all the variables

8v-4(5v-1)

We multiply parentheses

8v-20v+4

We add all the numbers together, and all the variables

-12v+4

Back to the equation:

-(-12v+4)



We get rid of parentheses

6v+12v-4+18=0

We add all the numbers together, and all the variables

18v+14=0

We move all terms containing v to the left, all other terms to the right

18v=-14

v=-14/18

v=-7/9

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