6(v+4)=-3(4v-4)+4v

Solution for 6(v+4)=-3(4v-4)+4v equation:

6(v+4)=-3(4v-4)+4v

We move all terms to the left:

6(v+4)-(-3(4v-4)+4v)=0

We multiply parentheses

6v-(-3(4v-4)+4v)+24=0


We calculate terms in parentheses: -(-3(4v-4)+4v), so:

-3(4v-4)+4v

We add all the numbers together, and all the variables

4v-3(4v-4)

We multiply parentheses

4v-12v+12

We add all the numbers together, and all the variables

-8v+12

Back to the equation:

-(-8v+12)


We get rid of parentheses

6v+8v-12+24=0

We add all the numbers together, and all the variables

14v+12=0

We move all terms containing v to the left, all other terms to the right

14v=-12

v=-12/14

v=-6/7