6(v+4)=-4(2v-7)+4v

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Solution for 6(v+4)=-4(2v-7)+4v equation: 



6(v+4)=-4(2v-7)+4v

We move all terms to the left:

6(v+4)-(-4(2v-7)+4v)=0

We multiply parentheses

6v-(-4(2v-7)+4v)+24=0



We calculate terms in parentheses: -(-4(2v-7)+4v), so:

-4(2v-7)+4v

We add all the numbers together, and all the variables

4v-4(2v-7)

We multiply parentheses

4v-8v+28

We add all the numbers together, and all the variables

-4v+28

Back to the equation:

-(-4v+28)



We get rid of parentheses

6v+4v-28+24=0

We add all the numbers together, and all the variables

10v-4=0

We move all terms containing v to the left, all other terms to the right

10v=4

v=4/10

v=2/5

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