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6(v+5)=-5(3v-4)+9v
We move all terms to the left:
6(v+5)-(-5(3v-4)+9v)=0
We multiply parentheses
6v-(-5(3v-4)+9v)+30=0
We calculate terms in parentheses: -(-5(3v-4)+9v), so:We get rid of parentheses
-5(3v-4)+9v
We add all the numbers together, and all the variables
9v-5(3v-4)
We multiply parentheses
9v-15v+20
We add all the numbers together, and all the variables
-6v+20
Back to the equation:
-(-6v+20)
6v+6v-20+30=0
We add all the numbers together, and all the variables
12v+10=0
We move all terms containing v to the left, all other terms to the right
12v=-10
v=-10/12
v=-5/6
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