6(v-2)-2=-2(-8v+1)-v

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Solution for 6(v-2)-2=-2(-8v+1)-v equation: 



6(v-2)-2=-2(-8v+1)-v

We move all terms to the left:

6(v-2)-2-(-2(-8v+1)-v)=0

We multiply parentheses

6v-(-2(-8v+1)-v)-12-2=0



We calculate terms in parentheses: -(-2(-8v+1)-v), so:

-2(-8v+1)-v

We add all the numbers together, and all the variables

-1v-2(-8v+1)

We multiply parentheses

-1v+16v-2

We add all the numbers together, and all the variables

15v-2

Back to the equation:

-(15v-2)



We add all the numbers together, and all the variables

6v-(15v-2)-14=0

We get rid of parentheses

6v-15v+2-14=0

We add all the numbers together, and all the variables

-9v-12=0

We move all terms containing v to the left, all other terms to the right

-9v=12

v=12/-9

v=-1+1/3

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