6(v-4)-5=-7(-3v+2)-5v

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Solution for 6(v-4)-5=-7(-3v+2)-5v equation: 



6(v-4)-5=-7(-3v+2)-5v

We move all terms to the left:

6(v-4)-5-(-7(-3v+2)-5v)=0

We multiply parentheses

6v-(-7(-3v+2)-5v)-24-5=0



We calculate terms in parentheses: -(-7(-3v+2)-5v), so:

-7(-3v+2)-5v

We add all the numbers together, and all the variables

-5v-7(-3v+2)

We multiply parentheses

-5v+21v-14

We add all the numbers together, and all the variables

16v-14

Back to the equation:

-(16v-14)



We add all the numbers together, and all the variables

6v-(16v-14)-29=0

We get rid of parentheses

6v-16v+14-29=0

We add all the numbers together, and all the variables

-10v-15=0

We move all terms containing v to the left, all other terms to the right

-10v=15

v=15/-10

v=-1+1/2

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