6(w+1)=-3(2w-4)+2w

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Solution for 6(w+1)=-3(2w-4)+2w equation: 



6(w+1)=-3(2w-4)+2w

We move all terms to the left:

6(w+1)-(-3(2w-4)+2w)=0

We multiply parentheses

6w-(-3(2w-4)+2w)+6=0



We calculate terms in parentheses: -(-3(2w-4)+2w), so:

-3(2w-4)+2w

We add all the numbers together, and all the variables

2w-3(2w-4)

We multiply parentheses

2w-6w+12

We add all the numbers together, and all the variables

-4w+12

Back to the equation:

-(-4w+12)



We get rid of parentheses

6w+4w-12+6=0

We add all the numbers together, and all the variables

10w-6=0

We move all terms containing w to the left, all other terms to the right

10w=6

w=6/10

w=3/5

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