6(w+1)=2(1-3w)-7

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Solution for 6(w+1)=2(1-3w)-7 equation: 



6(w+1)=2(1-3w)-7

We move all terms to the left:

6(w+1)-(2(1-3w)-7)=0

We add all the numbers together, and all the variables

6(w+1)-(2(-3w+1)-7)=0

We multiply parentheses

6w-(2(-3w+1)-7)+6=0



We calculate terms in parentheses: -(2(-3w+1)-7), so:

2(-3w+1)-7

We multiply parentheses

-6w+2-7

We add all the numbers together, and all the variables

-6w-5

Back to the equation:

-(-6w-5)



We get rid of parentheses

6w+6w+5+6=0

We add all the numbers together, and all the variables

12w+11=0

We move all terms containing w to the left, all other terms to the right

12w=-11

w=-11/12

w=-11/12

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