6(w+1)=2(1-3w)-8

Solution for 6(w+1)=2(1-3w)-8 equation:

6(w+1)=2(1-3w)-8

We move all terms to the left:

6(w+1)-(2(1-3w)-8)=0

We add all the numbers together, and all the variables

6(w+1)-(2(-3w+1)-8)=0

We multiply parentheses

6w-(2(-3w+1)-8)+6=0


We calculate terms in parentheses: -(2(-3w+1)-8), so:

2(-3w+1)-8

We multiply parentheses

-6w+2-8

We add all the numbers together, and all the variables

-6w-6

Back to the equation:

-(-6w-6)


We get rid of parentheses

6w+6w+6+6=0

We add all the numbers together, and all the variables

12w+12=0

We move all terms containing w to the left, all other terms to the right

12w=-12

w=-12/12

w=-1