6(w+2)-3(w+1)=w+1

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Solution for 6(w+2)-3(w+1)=w+1 equation:



6(w+2)-3(w+1)=w+1
We move all terms to the left:
6(w+2)-3(w+1)-(w+1)=0
We multiply parentheses
6w-3w-(w+1)+12-3=0
We get rid of parentheses
6w-3w-w-1+12-3=0
We add all the numbers together, and all the variables
2w+8=0
We move all terms containing w to the left, all other terms to the right
2w=-8
w=-8/2
w=-4

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