6(w+2)=40+4w

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Solution for 6(w+2)=40+4w equation: 



6(w+2)=40+4w

We move all terms to the left:

6(w+2)-(40+4w)=0

We add all the numbers together, and all the variables

6(w+2)-(4w+40)=0

We multiply parentheses

6w-(4w+40)+12=0

We get rid of parentheses

6w-4w-40+12=0

We add all the numbers together, and all the variables

2w-28=0

We move all terms containing w to the left, all other terms to the right

2w=28

w=28/2

w=14

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