6(w+5)-12=3(w-1)+4w

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Solution for 6(w+5)-12=3(w-1)+4w equation: 



6(w+5)-12=3(w-1)+4w

We move all terms to the left:

6(w+5)-12-(3(w-1)+4w)=0

We multiply parentheses

6w-(3(w-1)+4w)+30-12=0



We calculate terms in parentheses: -(3(w-1)+4w), so:

3(w-1)+4w

We add all the numbers together, and all the variables

4w+3(w-1)

We multiply parentheses

4w+3w-3

We add all the numbers together, and all the variables

7w-3

Back to the equation:

-(7w-3)



We add all the numbers together, and all the variables

6w-(7w-3)+18=0

We get rid of parentheses

6w-7w+3+18=0

We add all the numbers together, and all the variables

-1w+21=0

We move all terms containing w to the left, all other terms to the right

-w=-21

w=-21/-1

w=+21

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