6(w-2)+1=3(w+1)+10

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Solution for 6(w-2)+1=3(w+1)+10 equation: 



6(w-2)+1=3(w+1)+10

We move all terms to the left:

6(w-2)+1-(3(w+1)+10)=0

We multiply parentheses

6w-(3(w+1)+10)-12+1=0



We calculate terms in parentheses: -(3(w+1)+10), so:

3(w+1)+10

We multiply parentheses

3w+3+10

We add all the numbers together, and all the variables

3w+13

Back to the equation:

-(3w+13)



We add all the numbers together, and all the variables

6w-(3w+13)-11=0

We get rid of parentheses

6w-3w-13-11=0

We add all the numbers together, and all the variables

3w-24=0

We move all terms containing w to the left, all other terms to the right

3w=24

w=24/3

w=8

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