6(w-3)+6=2(2w+3)+2

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Solution for 6(w-3)+6=2(2w+3)+2 equation: 



6(w-3)+6=2(2w+3)+2

We move all terms to the left:

6(w-3)+6-(2(2w+3)+2)=0

We multiply parentheses

6w-(2(2w+3)+2)-18+6=0



We calculate terms in parentheses: -(2(2w+3)+2), so:

2(2w+3)+2

We multiply parentheses

4w+6+2

We add all the numbers together, and all the variables

4w+8

Back to the equation:

-(4w+8)



We add all the numbers together, and all the variables

6w-(4w+8)-12=0

We get rid of parentheses

6w-4w-8-12=0

We add all the numbers together, and all the variables

2w-20=0

We move all terms containing w to the left, all other terms to the right

2w=20

w=20/2

w=10

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