6(w-3)=2(w+1)

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Solution for 6(w-3)=2(w+1) equation: 



6(w-3)=2(w+1)

We move all terms to the left:

6(w-3)-(2(w+1))=0

We multiply parentheses

6w-(2(w+1))-18=0



We calculate terms in parentheses: -(2(w+1)), so:

2(w+1)

We multiply parentheses

2w+2

Back to the equation:

-(2w+2)



We get rid of parentheses

6w-2w-2-18=0

We add all the numbers together, and all the variables

4w-20=0

We move all terms containing w to the left, all other terms to the right

4w=20

w=20/4

w=5

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