6(w-4)+8w=2(w+12)

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Solution for 6(w-4)+8w=2(w+12) equation:



6(w-4)+8w=2(w+12)
We move all terms to the left:
6(w-4)+8w-(2(w+12))=0
We add all the numbers together, and all the variables
8w+6(w-4)-(2(w+12))=0
We multiply parentheses
8w+6w-(2(w+12))-24=0
We calculate terms in parentheses: -(2(w+12)), so:
2(w+12)
We multiply parentheses
2w+24
Back to the equation:
-(2w+24)
We add all the numbers together, and all the variables
14w-(2w+24)-24=0
We get rid of parentheses
14w-2w-24-24=0
We add all the numbers together, and all the variables
12w-48=0
We move all terms containing w to the left, all other terms to the right
12w=48
w=48/12
w=4

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