6(x)=4(x-4)+2(x-1)

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Solution for 6(x)=4(x-4)+2(x-1) equation:



6(x)=4(x-4)+2(x-1)
We move all terms to the left:
6(x)-(4(x-4)+2(x-1))=0
We calculate terms in parentheses: -(4(x-4)+2(x-1)), so:
4(x-4)+2(x-1)
We multiply parentheses
4x+2x-16-2
We add all the numbers together, and all the variables
6x-18
Back to the equation:
-(6x-18)
We get rid of parentheses
6x-6x+18=0
We add all the numbers together, and all the variables
18!=0
There is no solution for this equation

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