6(x+-4)+3x=12x+-8

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Solution for 6(x+-4)+3x=12x+-8 equation: 



6(x+-4)+3x=12x+-8

We move all terms to the left:

6(x+-4)+3x-(12x+-8)=0

We add all the numbers together, and all the variables

6(x-4)+3x-(12x-8)=0

We add all the numbers together, and all the variables

3x+6(x-4)-(12x-8)=0

We multiply parentheses

3x+6x-(12x-8)-24=0

We get rid of parentheses

3x+6x-12x+8-24=0

We add all the numbers together, and all the variables

-3x-16=0

We move all terms containing x to the left, all other terms to the right

-3x=16

x=16/-3

x=-5+1/3

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