6(x+1)+1=4x+2(1+x)

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Solution for 6(x+1)+1=4x+2(1+x) equation:



6(x+1)+1=4x+2(1+x)
We move all terms to the left:
6(x+1)+1-(4x+2(1+x))=0
We add all the numbers together, and all the variables
6(x+1)-(4x+2(x+1))+1=0
We multiply parentheses
6x-(4x+2(x+1))+6+1=0
We calculate terms in parentheses: -(4x+2(x+1)), so:
4x+2(x+1)
We multiply parentheses
4x+2x+2
We add all the numbers together, and all the variables
6x+2
Back to the equation:
-(6x+2)
We add all the numbers together, and all the variables
6x-(6x+2)+7=0
We get rid of parentheses
6x-6x-2+7=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation

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