6(x+1)+1=4x+2(1+x)

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Solution for 6(x+1)+1=4x+2(1+x) equation: 



6(x+1)+1=4x+2(1+x)

We move all terms to the left:

6(x+1)+1-(4x+2(1+x))=0

We add all the numbers together, and all the variables

6(x+1)-(4x+2(x+1))+1=0

We multiply parentheses

6x-(4x+2(x+1))+6+1=0



We calculate terms in parentheses: -(4x+2(x+1)), so:

4x+2(x+1)

We multiply parentheses

4x+2x+2

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We add all the numbers together, and all the variables

6x-(6x+2)+7=0

We get rid of parentheses

6x-6x-2+7=0

We add all the numbers together, and all the variables

5!=0

There is no solution for this equation

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