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6(x+1)+3x+3=1+7x
We move all terms to the left:
6(x+1)+3x+3-(1+7x)=0
We add all the numbers together, and all the variables
6(x+1)+3x-(7x+1)+3=0
We add all the numbers together, and all the variables
3x+6(x+1)-(7x+1)+3=0
We multiply parentheses
3x+6x-(7x+1)+6+3=0
We get rid of parentheses
3x+6x-7x-1+6+3=0
We add all the numbers together, and all the variables
2x+8=0
We move all terms containing x to the left, all other terms to the right
2x=-8
x=-8/2
x=-4
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