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6(x+1)+4=2x+4(2+x)
We move all terms to the left:
6(x+1)+4-(2x+4(2+x))=0
We add all the numbers together, and all the variables
6(x+1)-(2x+4(x+2))+4=0
We multiply parentheses
6x-(2x+4(x+2))+6+4=0
We calculate terms in parentheses: -(2x+4(x+2)), so:We add all the numbers together, and all the variables
2x+4(x+2)
We multiply parentheses
2x+4x+8
We add all the numbers together, and all the variables
6x+8
Back to the equation:
-(6x+8)
6x-(6x+8)+10=0
We get rid of parentheses
6x-6x-8+10=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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