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6(x+1)+4x=2(5x+3)
We move all terms to the left:
6(x+1)+4x-(2(5x+3))=0
We add all the numbers together, and all the variables
4x+6(x+1)-(2(5x+3))=0
We multiply parentheses
4x+6x-(2(5x+3))+6=0
We calculate terms in parentheses: -(2(5x+3)), so:We add all the numbers together, and all the variables
2(5x+3)
We multiply parentheses
10x+6
Back to the equation:
-(10x+6)
10x-(10x+6)+6=0
We get rid of parentheses
10x-10x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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