6(x+1)+4x=2(5x+3)

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Solution for 6(x+1)+4x=2(5x+3) equation: 



6(x+1)+4x=2(5x+3)

We move all terms to the left:

6(x+1)+4x-(2(5x+3))=0

We add all the numbers together, and all the variables

4x+6(x+1)-(2(5x+3))=0

We multiply parentheses

4x+6x-(2(5x+3))+6=0



We calculate terms in parentheses: -(2(5x+3)), so:

2(5x+3)

We multiply parentheses

10x+6

Back to the equation:

-(10x+6)



We add all the numbers together, and all the variables

10x-(10x+6)+6=0

We get rid of parentheses

10x-10x-6+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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