6(x+1)+5=19-2(4-3x)

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Solution for 6(x+1)+5=19-2(4-3x) equation: 



6(x+1)+5=19-2(4-3x)

We move all terms to the left:

6(x+1)+5-(19-2(4-3x))=0

We add all the numbers together, and all the variables

6(x+1)-(19-2(-3x+4))+5=0

We multiply parentheses

6x-(19-2(-3x+4))+6+5=0



We calculate terms in parentheses: -(19-2(-3x+4)), so:

19-2(-3x+4)

determiningTheFunctionDomain
-2(-3x+4)+19

We multiply parentheses

6x-8+19

We add all the numbers together, and all the variables

6x+11

Back to the equation:

-(6x+11)



We add all the numbers together, and all the variables

6x-(6x+11)+11=0

We get rid of parentheses

6x-6x-11+11=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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