6(x+1)+8x=2(x-3)

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Solution for 6(x+1)+8x=2(x-3) equation:



6(x+1)+8x=2(x-3)
We move all terms to the left:
6(x+1)+8x-(2(x-3))=0
We add all the numbers together, and all the variables
8x+6(x+1)-(2(x-3))=0
We multiply parentheses
8x+6x-(2(x-3))+6=0
We calculate terms in parentheses: -(2(x-3)), so:
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
We add all the numbers together, and all the variables
14x-(2x-6)+6=0
We get rid of parentheses
14x-2x+6+6=0
We add all the numbers together, and all the variables
12x+12=0
We move all terms containing x to the left, all other terms to the right
12x=-12
x=-12/12
x=-1

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