6(x+1)-10=4(x-1)+2

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Solution for 6(x+1)-10=4(x-1)+2 equation: 



6(x+1)-10=4(x-1)+2

We move all terms to the left:

6(x+1)-10-(4(x-1)+2)=0

We multiply parentheses

6x-(4(x-1)+2)+6-10=0



We calculate terms in parentheses: -(4(x-1)+2), so:

4(x-1)+2

We multiply parentheses

4x-4+2

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We add all the numbers together, and all the variables

6x-(4x-2)-4=0

We get rid of parentheses

6x-4x+2-4=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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