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6(x+1)-10=4(x-1)-2x
We move all terms to the left:
6(x+1)-10-(4(x-1)-2x)=0
We multiply parentheses
6x-(4(x-1)-2x)+6-10=0
We calculate terms in parentheses: -(4(x-1)-2x), so:We add all the numbers together, and all the variables
4(x-1)-2x
We add all the numbers together, and all the variables
-2x+4(x-1)
We multiply parentheses
-2x+4x-4
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
6x-(2x-4)-4=0
We get rid of parentheses
6x-2x+4-4=0
We add all the numbers together, and all the variables
4x=0
x=0/4
x=0
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