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6(x+1)-2=2x+4(1+x)
We move all terms to the left:
6(x+1)-2-(2x+4(1+x))=0
We add all the numbers together, and all the variables
6(x+1)-(2x+4(x+1))-2=0
We multiply parentheses
6x-(2x+4(x+1))+6-2=0
We calculate terms in parentheses: -(2x+4(x+1)), so:We add all the numbers together, and all the variables
2x+4(x+1)
We multiply parentheses
2x+4x+4
We add all the numbers together, and all the variables
6x+4
Back to the equation:
-(6x+4)
6x-(6x+4)+4=0
We get rid of parentheses
6x-6x-4+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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