6(x+1)-3=4x+2(2+x)

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Solution for 6(x+1)-3=4x+2(2+x) equation: 



6(x+1)-3=4x+2(2+x)

We move all terms to the left:

6(x+1)-3-(4x+2(2+x))=0

We add all the numbers together, and all the variables

6(x+1)-(4x+2(x+2))-3=0

We multiply parentheses

6x-(4x+2(x+2))+6-3=0



We calculate terms in parentheses: -(4x+2(x+2)), so:

4x+2(x+2)

We multiply parentheses

4x+2x+4

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

6x-(6x+4)+3=0

We get rid of parentheses

6x-6x-4+3=0

We add all the numbers together, and all the variables

-1!=0

There is no solution for this equation

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