6(x+1)-4=3(2x-1)+5

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Solution for 6(x+1)-4=3(2x-1)+5 equation: 


Simplifying
6(x + 1) + -4 = 3(2x + -1) + 5

Reorder the terms:
6(1 + x) + -4 = 3(2x + -1) + 5
(1 * 6 + x * 6) + -4 = 3(2x + -1) + 5
(6 + 6x) + -4 = 3(2x + -1) + 5

Reorder the terms:
6 + -4 + 6x = 3(2x + -1) + 5

Combine like terms: 6 + -4 = 2
2 + 6x = 3(2x + -1) + 5

Reorder the terms:
2 + 6x = 3(-1 + 2x) + 5
2 + 6x = (-1 * 3 + 2x * 3) + 5
2 + 6x = (-3 + 6x) + 5

Reorder the terms:
2 + 6x = -3 + 5 + 6x

Combine like terms: -3 + 5 = 2
2 + 6x = 2 + 6x

Add '-2' to each side of the equation.
2 + -2 + 6x = 2 + -2 + 6x

Combine like terms: 2 + -2 = 0
0 + 6x = 2 + -2 + 6x
6x = 2 + -2 + 6x

Combine like terms: 2 + -2 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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