6(x+1)-5(x-2)=20

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Solution for 6(x+1)-5(x-2)=20 equation:


Simplifying
6(x + 1) + -5(x + -2) = 20

Reorder the terms:
6(1 + x) + -5(x + -2) = 20
(1 * 6 + x * 6) + -5(x + -2) = 20
(6 + 6x) + -5(x + -2) = 20

Reorder the terms:
6 + 6x + -5(-2 + x) = 20
6 + 6x + (-2 * -5 + x * -5) = 20
6 + 6x + (10 + -5x) = 20

Reorder the terms:
6 + 10 + 6x + -5x = 20

Combine like terms: 6 + 10 = 16
16 + 6x + -5x = 20

Combine like terms: 6x + -5x = 1x
16 + 1x = 20

Solving
16 + 1x = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 1x = 20 + -16

Combine like terms: 16 + -16 = 0
0 + 1x = 20 + -16
1x = 20 + -16

Combine like terms: 20 + -16 = 4
1x = 4

Divide each side by '1'.
x = 4

Simplifying
x = 4

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