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6(x+1)-5=1+6x
We move all terms to the left:
6(x+1)-5-(1+6x)=0
We add all the numbers together, and all the variables
6(x+1)-(6x+1)-5=0
We multiply parentheses
6x-(6x+1)+6-5=0
We get rid of parentheses
6x-6x-1+6-5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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