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6(x+1)-5=2x+4(-1+x)
We move all terms to the left:
6(x+1)-5-(2x+4(-1+x))=0
We add all the numbers together, and all the variables
6(x+1)-(2x+4(x-1))-5=0
We multiply parentheses
6x-(2x+4(x-1))+6-5=0
We calculate terms in parentheses: -(2x+4(x-1)), so:We add all the numbers together, and all the variables
2x+4(x-1)
We multiply parentheses
2x+4x-4
We add all the numbers together, and all the variables
6x-4
Back to the equation:
-(6x-4)
6x-(6x-4)+1=0
We get rid of parentheses
6x-6x+4+1=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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