6(x+1)-5=3(x+4)+11

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Solution for 6(x+1)-5=3(x+4)+11 equation:



6(x+1)-5=3(x+4)+11
We move all terms to the left:
6(x+1)-5-(3(x+4)+11)=0
We multiply parentheses
6x-(3(x+4)+11)+6-5=0
We calculate terms in parentheses: -(3(x+4)+11), so:
3(x+4)+11
We multiply parentheses
3x+12+11
We add all the numbers together, and all the variables
3x+23
Back to the equation:
-(3x+23)
We add all the numbers together, and all the variables
6x-(3x+23)+1=0
We get rid of parentheses
6x-3x-23+1=0
We add all the numbers together, and all the variables
3x-22=0
We move all terms containing x to the left, all other terms to the right
3x=22
x=22/3
x=7+1/3

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