6(x+1)-5=3(x+4)+11

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Solution for 6(x+1)-5=3(x+4)+11 equation: 



6(x+1)-5=3(x+4)+11

We move all terms to the left:

6(x+1)-5-(3(x+4)+11)=0

We multiply parentheses

6x-(3(x+4)+11)+6-5=0



We calculate terms in parentheses: -(3(x+4)+11), so:

3(x+4)+11

We multiply parentheses

3x+12+11

We add all the numbers together, and all the variables

3x+23

Back to the equation:

-(3x+23)



We add all the numbers together, and all the variables

6x-(3x+23)+1=0

We get rid of parentheses

6x-3x-23+1=0

We add all the numbers together, and all the variables

3x-22=0

We move all terms containing x to the left, all other terms to the right

3x=22

x=22/3

x=7+1/3

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