6(x+1)-5x=8+2(x-2)

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Solution for 6(x+1)-5x=8+2(x-2) equation: 



6(x+1)-5x=8+2(x-2)

We move all terms to the left:

6(x+1)-5x-(8+2(x-2))=0

We add all the numbers together, and all the variables

-5x+6(x+1)-(8+2(x-2))=0

We multiply parentheses

-5x+6x-(8+2(x-2))+6=0



We calculate terms in parentheses: -(8+2(x-2)), so:

8+2(x-2)

determiningTheFunctionDomain
2(x-2)+8

We multiply parentheses

2x-4+8

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

x-(2x+4)+6=0

We get rid of parentheses

x-2x-4+6=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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