6(x+1)-5x=8+2x(x-1)

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Solution for 6(x+1)-5x=8+2x(x-1) equation: 



6(x+1)-5x=8+2x(x-1)

We move all terms to the left:

6(x+1)-5x-(8+2x(x-1))=0

We add all the numbers together, and all the variables

-5x+6(x+1)-(8+2x(x-1))=0

We multiply parentheses

-5x+6x-(8+2x(x-1))+6=0



We calculate terms in parentheses: -(8+2x(x-1)), so:

8+2x(x-1)

determiningTheFunctionDomain
2x(x-1)+8

We multiply parentheses

2x^2-2x+8

Back to the equation:

-(2x^2-2x+8)



We add all the numbers together, and all the variables

x-(2x^2-2x+8)+6=0

We get rid of parentheses

-2x^2+x+2x-8+6=0

We add all the numbers together, and all the variables

-2x^2+3x-2=0

a = -2; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·(-2)·(-2)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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