6(x+1)=2(1-3x)-8

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Solution for 6(x+1)=2(1-3x)-8 equation: 



6(x+1)=2(1-3x)-8

We move all terms to the left:

6(x+1)-(2(1-3x)-8)=0

We add all the numbers together, and all the variables

6(x+1)-(2(-3x+1)-8)=0

We multiply parentheses

6x-(2(-3x+1)-8)+6=0



We calculate terms in parentheses: -(2(-3x+1)-8), so:

2(-3x+1)-8

We multiply parentheses

-6x+2-8

We add all the numbers together, and all the variables

-6x-6

Back to the equation:

-(-6x-6)



We get rid of parentheses

6x+6x+6+6=0

We add all the numbers together, and all the variables

12x+12=0

We move all terms containing x to the left, all other terms to the right

12x=-12

x=-12/12

x=-1

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