6(x+1)=2(3+3x)

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Solution for 6(x+1)=2(3+3x) equation:



6(x+1)=2(3+3x)
We move all terms to the left:
6(x+1)-(2(3+3x))=0
We add all the numbers together, and all the variables
6(x+1)-(2(3x+3))=0
We multiply parentheses
6x-(2(3x+3))+6=0
We calculate terms in parentheses: -(2(3x+3)), so:
2(3x+3)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
We get rid of parentheses
6x-6x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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