6(x+1)=4(1+1/3x)+6+3x

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Solution for 6(x+1)=4(1+1/3x)+6+3x equation: 



6(x+1)=4(1+1/3x)+6+3x

We move all terms to the left:

6(x+1)-(4(1+1/3x)+6+3x)=0



Domain of the equation: 3x)+6+3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

6(x+1)-(4(1/3x+1)+6+3x)=0

We multiply parentheses

6x-(4(1/3x+1)+6+3x)+6=0

We multiply all the terms by the denominator


6x*3x+1)+6+3x)-(4(1+6*3x+1)+6+3x)=0

We add all the numbers together, and all the variables

6x*3x+1)+6+3x)-(4(6*3x+2)+6+3x)=0

Wy multiply elements

18x^2+1)+6+3x)-(4(6*3x+2)+6+3x)=0

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