6(x+1)=8(2x-8)

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Solution for 6(x+1)=8(2x-8) equation: 



6(x+1)=8(2x-8)

We move all terms to the left:

6(x+1)-(8(2x-8))=0

We multiply parentheses

6x-(8(2x-8))+6=0



We calculate terms in parentheses: -(8(2x-8)), so:

8(2x-8)

We multiply parentheses

16x-64

Back to the equation:

-(16x-64)



We get rid of parentheses

6x-16x+64+6=0

We add all the numbers together, and all the variables

-10x+70=0

We move all terms containing x to the left, all other terms to the right

-10x=-70

x=-70/-10

x=+7

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