6(x+1)=8x-3(x-7)

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Solution for 6(x+1)=8x-3(x-7) equation: 



6(x+1)=8x-3(x-7)

We move all terms to the left:

6(x+1)-(8x-3(x-7))=0

We multiply parentheses

6x-(8x-3(x-7))+6=0



We calculate terms in parentheses: -(8x-3(x-7)), so:

8x-3(x-7)

We multiply parentheses

8x-3x+21

We add all the numbers together, and all the variables

5x+21

Back to the equation:

-(5x+21)



We get rid of parentheses

6x-5x-21+6=0

We add all the numbers together, and all the variables

x-15=0

We move all terms containing x to the left, all other terms to the right

x=15

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