6(x+12)=4(x+3)+1

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Solution for 6(x+12)=4(x+3)+1 equation: 



6(x+12)=4(x+3)+1

We move all terms to the left:

6(x+12)-(4(x+3)+1)=0

We multiply parentheses

6x-(4(x+3)+1)+72=0



We calculate terms in parentheses: -(4(x+3)+1), so:

4(x+3)+1

We multiply parentheses

4x+12+1

We add all the numbers together, and all the variables

4x+13

Back to the equation:

-(4x+13)



We get rid of parentheses

6x-4x-13+72=0

We add all the numbers together, and all the variables

2x+59=0

We move all terms containing x to the left, all other terms to the right

2x=-59

x=-59/2

x=-29+1/2

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