6(x+2)+15=7(x+1)+16

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Solution for 6(x+2)+15=7(x+1)+16 equation: 



6(x+2)+15=7(x+1)+16

We move all terms to the left:

6(x+2)+15-(7(x+1)+16)=0

We multiply parentheses

6x-(7(x+1)+16)+12+15=0



We calculate terms in parentheses: -(7(x+1)+16), so:

7(x+1)+16

We multiply parentheses

7x+7+16

We add all the numbers together, and all the variables

7x+23

Back to the equation:

-(7x+23)



We add all the numbers together, and all the variables

6x-(7x+23)+27=0

We get rid of parentheses

6x-7x-23+27=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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