6(x+2)+2x-4=8(x-2)+

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Solution for 6(x+2)+2x-4=8(x-2)+ equation: 



6(x+2)+2x-4=8(x-2)+

We move all terms to the left:

6(x+2)+2x-4-(8(x-2)+)=0

We add all the numbers together, and all the variables

2x+6(x+2)-(8(x-2)+)-4=0

We multiply parentheses

2x+6x-(8(x-2)+)+12-4=0



We calculate terms in parentheses: -(8(x-2)+), so:

8(x-2)+

We add all the numbers together, and all the variables

8(x-2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We add all the numbers together, and all the variables

8x-(8x-16)+8=0

We get rid of parentheses

8x-8x+16+8=0

We add all the numbers together, and all the variables

24!=0

There is no solution for this equation

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