6(x+2)+2x-4=8(x-2)+3

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Solution for 6(x+2)+2x-4=8(x-2)+3 equation: 


Simplifying
6(x + 2) + 2x + -4 = 8(x + -2) + 3

Reorder the terms:
6(2 + x) + 2x + -4 = 8(x + -2) + 3
(2 * 6 + x * 6) + 2x + -4 = 8(x + -2) + 3
(12 + 6x) + 2x + -4 = 8(x + -2) + 3

Reorder the terms:
12 + -4 + 6x + 2x = 8(x + -2) + 3

Combine like terms: 12 + -4 = 8
8 + 6x + 2x = 8(x + -2) + 3

Combine like terms: 6x + 2x = 8x
8 + 8x = 8(x + -2) + 3

Reorder the terms:
8 + 8x = 8(-2 + x) + 3
8 + 8x = (-2 * 8 + x * 8) + 3
8 + 8x = (-16 + 8x) + 3

Reorder the terms:
8 + 8x = -16 + 3 + 8x

Combine like terms: -16 + 3 = -13
8 + 8x = -13 + 8x

Add '-8x' to each side of the equation.
8 + 8x + -8x = -13 + 8x + -8x

Combine like terms: 8x + -8x = 0
8 + 0 = -13 + 8x + -8x
8 = -13 + 8x + -8x

Combine like terms: 8x + -8x = 0
8 = -13 + 0
8 = -13

Solving
8 = -13

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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