6(x+2)+2x-4=8(x-2)/8

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Solution for 6(x+2)+2x-4=8(x-2)/8 equation: 



6(x+2)+2x-4=8(x-2)/8

We move all terms to the left:

6(x+2)+2x-4-(8(x-2)/8)=0

We add all the numbers together, and all the variables

2x+6(x+2)-(8(x-2)/8)-4=0

We multiply parentheses

2x+6x-(8(x-2)/8)+12-4=0

We multiply all the terms by the denominator


2x*8)+6x*8)-(8(x-2)+12*8)-4*8)=0

We add all the numbers together, and all the variables

2x*8)+6x*8)-(8(x=0

Wy multiply elements

128x^3=0

We do not support expression: x^3

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