6(x+2)+2x-4=8(x-2+8

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Solution for 6(x+2)+2x-4=8(x-2+8 equation: 



6(x+2)+2x-4=8(x-2+8

We move all terms to the left:

6(x+2)+2x-4-(8(x-2+8)=0

We add all the numbers together, and all the variables

6(x+2)+2x-(8(x+6)-4=0

We add all the numbers together, and all the variables

2x+6(x+2)-(8(x+6)-4=0

We multiply parentheses

2x+6x-(8(x+6)-4+12=0

We add all the numbers together, and all the variables

8x-(8(x+6)-4+12=0

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