6(x+2)+3=-7(x-5)-3

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Solution for 6(x+2)+3=-7(x-5)-3 equation: 



6(x+2)+3=-7(x-5)-3

We move all terms to the left:

6(x+2)+3-(-7(x-5)-3)=0

We multiply parentheses

6x-(-7(x-5)-3)+12+3=0



We calculate terms in parentheses: -(-7(x-5)-3), so:

-7(x-5)-3

We multiply parentheses

-7x+35-3

We add all the numbers together, and all the variables

-7x+32

Back to the equation:

-(-7x+32)



We add all the numbers together, and all the variables

6x-(-7x+32)+15=0

We get rid of parentheses

6x+7x-32+15=0

We add all the numbers together, and all the variables

13x-17=0

We move all terms containing x to the left, all other terms to the right

13x=17

x=17/13

x=1+4/13

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