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6(x+2)+3=2(2x+6)+7
We move all terms to the left:
6(x+2)+3-(2(2x+6)+7)=0
We multiply parentheses
6x-(2(2x+6)+7)+12+3=0
We calculate terms in parentheses: -(2(2x+6)+7), so:We add all the numbers together, and all the variables
2(2x+6)+7
We multiply parentheses
4x+12+7
We add all the numbers together, and all the variables
4x+19
Back to the equation:
-(4x+19)
6x-(4x+19)+15=0
We get rid of parentheses
6x-4x-19+15=0
We add all the numbers together, and all the variables
2x-4=0
We move all terms containing x to the left, all other terms to the right
2x=4
x=4/2
x=2
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