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6(x+2)+3=2x+4(5+x)
We move all terms to the left:
6(x+2)+3-(2x+4(5+x))=0
We add all the numbers together, and all the variables
6(x+2)-(2x+4(x+5))+3=0
We multiply parentheses
6x-(2x+4(x+5))+12+3=0
We calculate terms in parentheses: -(2x+4(x+5)), so:We add all the numbers together, and all the variables
2x+4(x+5)
We multiply parentheses
2x+4x+20
We add all the numbers together, and all the variables
6x+20
Back to the equation:
-(6x+20)
6x-(6x+20)+15=0
We get rid of parentheses
6x-6x-20+15=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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