6(x+2)+4(3-x)=35

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Solution for 6(x+2)+4(3-x)=35 equation: 



6(x+2)+4(3-x)=35

We move all terms to the left:

6(x+2)+4(3-x)-(35)=0

We add all the numbers together, and all the variables

6(x+2)+4(-1x+3)-35=0

We multiply parentheses

6x-4x+12+12-35=0

We add all the numbers together, and all the variables

2x-11=0

We move all terms containing x to the left, all other terms to the right

2x=11

x=11/2

x=5+1/2

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